BUTTON PULLDOWN QUESTION

Question

hello. I want to use the button as a pull-down. I am using nrf52832, and the button and circuit part are composed of pull-down and the code is written as follows. 
 #define LED_RED 17
#define LED_GREEN 18

int main(void)
{
 nrf_gpio_cfg_output(LED_RED); 
 nrf_gpio_cfg_output(LED_GREEN);
 nrf_gpio_cfg_input(14, NRF_GPIO_PIN_PULLDOWN);
 
 for(;;)
 {
 if(nrf_gpio_pin_read(14) == 1)
 {
 nrf_gpio_pin_clear(LED_RED);
 nrf_gpio_pin_set(LED_GREEN);
 }
 else
 {
 nrf_gpio_pin_clear(LED_GREEN);
 nrf_gpio_pin_set(LED_RED);
 }
 }
} 
 
 However, even if the button is pressed, it always behaves as 0. I want to know why... 
 Ask for help.

user97123 · Accepted Answer

I have solved this problem! It happened because I misunderstood the circuit. The chip I used is nrf52832 and is written from sdk15.2. Not DK. Thanks for the reply!

And for other developers who may have the same problem, in NRF52dk, GPIOs 13~17 are internally pulled-up, so if you use it as a button, you must do a pull-up set. Also, if you use GPIO 13~17 as a pull-down in a non-dk version, you should not use the bsp handler. Actually I think the best way is to use 20 or more GPIOs with nothing defined...
 
I am writing the answer through a translator, there may be mistranslations. 
 Thank you!!